program of equation

#include<stdio.h>
#include<conio.h>
int main()
{
clrscr();
int x,y,equat;
printf("enter the value of x:");
scanf("%d",&x);
printf("enter the value of y:");
scanf("%d",&y);
(equat=((x*x)*(y*y)*(x+y)/(x*x*x*x+y*y*y*y*y*y*y*y*y*y)*(x+y)));
printf("the required value is:");
printf("%d",equat);
getch();
return(0);
}